TS EAMCET · Physics · Magnetic Effects of Current

The resistance in following circuit are $R_{1} = R_{2} = R_{3} = 6.0 Ω .$ The emf of the battery is $12$ volts. When switch $S$ is closed, the potential across resistance $R_{1}$ is changed by an amount.

A $- 2 V$
B $+ 2 V$
C $- 4 V$
D $+ 4 V$

Verified Solution

Answer & Solution

Correct Answer

(A) $- 2 V$

Step-by-step Solution

Detailed explanation

When the switch S is open, no current will flow through resistance R2, so the total resistance will be R=R1+R2=6+6=12 Ω as both are in series combination. Thus the current through R1, I=1212=1 A The potential difference across R1, V1=IR=1×6=6 V…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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The resistance in following circuit are R1=R2=R3=6.0Ω. The emf of the battery is 12 volts. When switch Sis closed, the potential across resistance R1 is changed by an amount.

Step-by-step Solution

The resistance in following circuit are $R_{1} = R_{2} = R_{3} = 6.0 Ω .$ The emf of the battery is $12$ volts. When switch $S$ is closed, the potential across resistance $R_{1}$ is changed by an amount.