TS EAMCET · Physics · Magnetic Effects of Current
A steady current \(I\) flows through a wire with one end at \(O\) and the other end extending upto infinity as shown in the figure. The magnetic field at a point \(P\), located at a distance \(d\) from \(O\) is 
- A \(\frac{\mu_0 I}{4 \pi d \cos \alpha}(1-\sin \alpha)\)
- B \(\frac{\mu_0 l}{2 \pi d \cos \alpha}(1-\sin \alpha)\)
- C \(\frac{\mu_0 l}{4 \pi d}\)
- D \(\frac{\mu_0 I}{4 \pi d \sin \alpha}(1-\cos \alpha)\)
Answer & Solution
Correct Answer
(D) \(\frac{\mu_0 I}{4 \pi d \sin \alpha}(1-\cos \alpha)\)
Step-by-step Solution
Detailed explanation
From result of field of a long wire, we have \( \beta=\frac{\mu_0}{4 \pi} \times \frac{I}{r} \times\left(\sin \theta_1-\sin \theta_2\right) \) Here,…
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