TS EAMCET · Physics · Magnetic Properties of Matter
Let \(m\) and \(r\) are the dipole moment and radius of earth respectively. Then, the earth's magnetic field at the equator is
- A \(\frac{\mu_0}{4 \pi} \frac{m}{r^3}\)
- B \(\frac{\mu_0}{8 \pi} \frac{m}{r^3}\)
- C \(\frac{\mu_0}{2 \pi} \frac{m}{r^3}\)
- D \(\frac{\mu_0}{\pi} \frac{m}{r^3}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mu_0}{4 \pi} \frac{m}{r^3}\)
Step-by-step Solution
Detailed explanation
Given, \(m=\) magnetic dipole moment of earth \(r=\) radius of earth It is assumed that earth has a bar magnet inside it Hence, magnetic field at any point on equitorial line of earth's bar magnet is given as, \(B=\frac{\mu_0}{4 \pi} \cdot \frac{m}{r^3}\)
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