TS EAMCET · Physics · Nuclear Physics
The half life of neutron is 693 seconds. What fraction of neutrons will decay when a beam of neutrons, having kinetic energy of 0.084 \(\mathrm{eV}\), travells a distance of \(1 \mathrm{~km}\) ? (mass of neutron \(=1.68 \times 10^{-27} \mathrm{~kg}\), and \(\ln 2=0.693\) )
- A \(0.25 \times 10^{\wedge}-5\)
- B \(0.5 \times 10^{\wedge}-5\)
- C \(0.8 \times 10^{\wedge}-5\)
- D \(10^{\wedge}-5\)
Answer & Solution
Correct Answer
(A) \(0.25 \times 10^{\wedge}-5\)
Step-by-step Solution
Detailed explanation
Given, the half-life of neutron, \(t_{1 / 2}=693 \mathrm{sec}\) Kinetic energy of neutron \(=0.084 \mathrm{eV}\)…
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