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TS EAMCET · Physics · Electrostatics

The volume charge density in a spherical ball of radius \(R\) varies with distance \(r\) from the centre as \(\rho(r)=\rho_0\left[1-\left(\frac{r}{R}\right)^3\right]\), where, \(\rho_0\) is a constant. The radius at which the field would be maximum is

  1. A \(\frac{R}{2^{1 / 3}}\)
  2. B \(R\)
  3. C \(\frac{R}{2}\)
  4. D \(\frac{R^{1 / 3}}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{R}{2^{1 / 3}}\)

Step-by-step Solution

Detailed explanation

Given, \(\quad \rho(r)=\rho_0\left[1-\left(\frac{r}{R}\right)^3\right]\) So, effective charge at \(r\) is \(q(r)=\int \rho(r) \cdot V\) \[ =\rho_0\left[1-\left(\frac{r}{R}\right)^3\right] \frac{4}{3} \pi r^3 \] For maximum value of field,…
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