ExamBro
ExamBro
TS EAMCET · Physics · Waves and Sound

The equation of a transverse wave propagating on a stretched string is given by \(y=3 \sin (4 x+200 \mathrm{t})\), where \(x\) and \(y\) are in metre and the time ' t ' is in second. If the tension applied to the string is 500 N, the linear density of the string is

  1. A \(0.25 \mathrm{~kg} \mathrm{~m}^{-1}\)
  2. B \(0.4 \mathrm{~kg} \mathrm{~m}^{-1}\)
  3. C \(0.2 \mathrm{~kg} \mathrm{~m}^{-1}\)
  4. D \(0.1 \mathrm{~kg} \mathrm{~m}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(0.2 \mathrm{~kg} \mathrm{~m}^{-1}\)

Step-by-step Solution

Detailed explanation

\(k = 4 \ \mathrm{m}^{-1}\), \(\omega = 200 \ \mathrm{rad/s}\) \(v = \frac{\omega}{k} = \frac{200}{4} = 50 \ \mathrm{m/s}\) \(\mu = \frac{T}{v^2} = \frac{500}{(50)^2} = \frac{500}{2500} = 0.2 \ \mathrm{kg \ m^{-1}}\)
Same subject
Explore more questions on app
From TS EAMCET
Explore more questions on app