TS EAMCET · Physics · Motion In One Dimension
A body starts from rest with uniform acceleration. If its velocity after \(\mathrm{n}^{\text {th }}\) second (last second) is ' \(\mathrm{V}\) ' then its displacement in the last two seconds is
- A \(\frac{2 V(n+1)}{n}\)
- B \(\frac{\mathrm{V}(\mathrm{n}+1)}{\mathrm{n}}\)
- C \(\frac{V(n-1)}{n}\)
- D \(\frac{2 V(n-1)}{n}\)
Answer & Solution
Correct Answer
(D) \(\frac{2 V(n-1)}{n}\)
Step-by-step Solution
Detailed explanation
From the equation of motion \[ \begin{aligned} & \mathrm{v}=\mathrm{u}+\text { at } \\ & \mathrm{v}=0+\text { an } \Rightarrow \mathrm{a}=\frac{\mathrm{v}}{\mathrm{n}} \end{aligned} \] It's displacement in the last two second…
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