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TS EAMCET · Physics · Electrostatics

There are two thin wire rings, each of radius \(R\), whose axes coincide. The charges of the rings are \(q\) and \(-\mathrm{q}\). The magnitude of potential difference between the centres of the rings separated by a distance \(\sqrt{3} \mathrm{R}\) is

  1. A 0
  2. B \(\frac{\mathrm{q}}{4 \pi \varepsilon_0 \mathrm{R}}\)
  3. C \(\frac{\mathrm{q}}{4 \pi \varepsilon_0 \mathrm{R}} \frac{1}{\sqrt{3} \mathrm{R}}\)
  4. D \(\frac{\mathrm{q}}{2 \pi \varepsilon_0 \mathrm{R}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{\mathrm{q}}{4 \pi \varepsilon_0 \mathrm{R}}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \mathrm{V}_{\mathrm{A}}=\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{q}}{\mathrm{R}}-\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{q}}{\sqrt{\mathrm{R}^2+3 \mathrm{R}^2}} \\ & \mathrm{~V}_{\mathrm{B}}=\frac{-1}{4 \pi \varepsilon_0}…

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