TS EAMCET · Physics · Electromagnetic Induction

A toroid has an iron core with an internal magnetic field of $10 πmT$ , when the current in the winding of 1500 turns per meter is $10 A$ . Deternine the field due to magnetization $(μ_{0} = 4 π \times 10^{- 7} {Hm}^{- 1})$

A $(4 π) mT$
B $(10 π) mT$
C $(\frac{8}{π}) mT$
D $(\frac{π}{4}) mT$

Verified Solution

Answer & Solution

Correct Answer

(A) $(4 π) mT$

Step-by-step Solution

Detailed explanation

Magnetic field due to toroid is B=μ0nI=4π×10-7×1500×10=6π×10-3 T Magnetic field due to iron core is B0=10π mT=10π×10-3 T Magnetic field due to magnetisation is Bm=B0-B=10π×10-3-6π×10-3…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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A toroid has an iron core with an internal magnetic field of 10πmT, when the current in the winding of 1500 turns per meter is 10 A. Deternine the field due to magnetization μ0=4π×10-7Hm-1

Step-by-step Solution

A toroid has an iron core with an internal magnetic field of $10 πmT$ , when the current in the winding of 1500 turns per meter is $10 A$ . Deternine the field due to magnetization $(μ_{0} = 4 π \times 10^{- 7} {Hm}^{- 1})$