TS EAMCET · Physics · Electrostatics
Two point charges \(-10 \mu \mathrm{C}\) and \(+5 \mu \mathrm{C}\) are situated on \(X\)-axis at \(x=0\) and \(x=\sqrt{2} \mathrm{~m}\). The point along the \(X\)-axis where the electric field becomes zero is
- A \(x=(\sqrt{2}-1) \mathrm{m}\)
- B \(x=2(\sqrt{2}-1) \mathrm{m}\)
- C \(\quad x=2(\sqrt{2}+1) \mathrm{m}\)
- D \(x=(\sqrt{2}+1) \mathrm{m}\)
Answer & Solution
Correct Answer
(C) \(\quad x=2(\sqrt{2}+1) \mathrm{m}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { (c) } \mathrm{q}_1=-10 \mu \mathrm{C}, \mathrm{q}_2=5 \mu \mathrm{C} \\ & \mathrm{r}=\sqrt{2} \mathrm{~m}\end{aligned}\) The point on \(x\)-axis where electric field is zero,…
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