TS EAMCET · Physics · Waves and Sound
If the length of a stretched string is shortened by \(40 \%\) and the tension is increased by \(44 \%\), then the ratio of the final and initial fundamental frequencies is :
- A \(2: 1\)
- B \(3: 2\)
- C \(3: 4\)
- D \(1: 3\)
Answer & Solution
Correct Answer
(A) \(2: 1\)
Step-by-step Solution
Detailed explanation
Fundamental frequency, \(n=\frac{1}{2 l} \sqrt{\frac{T}{m}}\) Initial frequency, \(n_1=\frac{1}{2 l} \sqrt{\frac{T}{m}}\) New length, \(l^{\prime}=l-\frac{l \times 40}{100}=0.6 l\) New tension, \(T^{\prime}=T+\frac{T \times 44}{100}\) \(=1.44 \mathrm{~T}\) New frequency…
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