TS EAMCET · Physics · Magnetic Effects of Current

Two capacitors, $C_{1} = 2 mF$ and $C_{2} = 8 mF$ are connected in series across a $300 V$ source. Then

A The charge on each capacitor is $480 \times 10^{- 3} C$
B The potential difference across $C_{1}$ is $60 V$
C The potential difference across $C_{2}$ is $240 V$
D The energy stored in the system is $5.2 \times 10^{- 2} J$

Verified Solution

Answer & Solution

Correct Answer

(A) The charge on each capacitor is $480 \times 10^{- 3} C$

Step-by-step Solution

Detailed explanation

The capacitors are connected in series then the net capacitance will be, Cnet=C1×C2C1+C2=2×82+8=1.6 mF, then the net charge will be, Qnet=CnetV=1.6×10-3×300=480×10-3 C, which will be same in each capacitor now potential difference across each…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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Two capacitors, C1=2mF and C2=8mF are connected in series across a 300 V source. Then

Step-by-step Solution

Two capacitors, $C_{1} = 2 mF$ and $C_{2} = 8 mF$ are connected in series across a $300 V$ source. Then