TS EAMCET · Physics · Dual Nature of Matter
A monochromatic light of wavelength \(\lambda\) ejects photoelectrons from a metal surface with work function \((\phi) 2.4 \mathrm{eV}\). These photoelectrons are made to collide with hydrogen atoms in ground state. The maximum value of \(\lambda\) for which hydrogen atom may be ionised is [take, \(h c=1240 \mathrm{eV}-\mathrm{nm}\) ]
- A \(80 \mathrm{~nm}\)
- B \(77.5 \mathrm{~nm}\)
- C \(75.5 \mathrm{~nm}\)
- D \(85 \mathrm{~nm}\)
Answer & Solution
Correct Answer
(B) \(77.5 \mathrm{~nm}\)
Step-by-step Solution
Detailed explanation
Given, work-function, \(\phi=2.4 \mathrm{eV}\) Energy required to ionise \(\mathrm{H}\)-atom in ground state \(=13.6 \mathrm{eV}\) According to photoelectric equation, \(E=\mathrm{KE}+\phi \Rightarrow \frac{h c}{\lambda}=\mathrm{KE}+\phi\)…
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