TS EAMCET · Physics · Mechanical Properties of Fluids
The excess pressure inside a soap bubble of radius 0.5 cm is balanced by the pressure due to an oil column of height 4 mm . If the density of the oil is \(900 \mathrm{~kg} \mathrm{~m}^{-3}\), then the surface tension of the soap solution is (Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(9 \times 10^{-2} \mathrm{Nm}^{-1}\)
- B \(2.25 \times 10^{-2} \mathrm{Nm}^{-1}\)
- C \(4.5 \times 10^{-2} \mathrm{Nm}^{-1}\)
- D \(7 \times 10^{-2} \mathrm{Nm}^{-1}\)
Answer & Solution
Correct Answer
(C) \(4.5 \times 10^{-2} \mathrm{Nm}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, Radius of soap bubble, \(\mathrm{R}=0.5 \mathrm{~cm}\) Height of oil column, \(\mathrm{h}=4 \times 10^{-3} \mathrm{~m}\) Density of the oil, \(\rho=900 \mathrm{~kg} \mathrm{~m}^{-3}\) Excess pressure inside soap bubble, \(\mathrm{P}=\frac{4 \mathrm{~S}}{\mathrm{R}}\)…
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