TS EAMCET · Physics · Semiconductors
In a \(p-n\) junction diode, an electric field of magnitude \(2 \times 10^5 \mathrm{~V} /\) mexists in the depletion region. A particle with charge \(-3 e\) can diffuse from \(n\)-side to \(p\)-side, if it has minimum kinetic energy \(0.6 \mathrm{eV}\). The width of the depletion region of the \(p-n\) junction is
- A \(300 \mathrm{~nm}\)
- B \(600 \mathrm{~nm}\)
- C \(1000 \mathrm{~nm}\)
- D \(1200 \mathrm{~nm}\)
Answer & Solution
Correct Answer
(C) \(1000 \mathrm{~nm}\)
Step-by-step Solution
Detailed explanation
\[ \Rightarrow \quad \beta=34 \] For depletion width \(d\), developed potential is \[ V=E \cdot d=2 \times 10^5 \times d \] For charged particle, experienced potential is \[ V=\frac{\text { Energy }}{\text { Charge }}=\frac{0 \cdot 6 \mathrm{eV}}{3 e}=0 \cdot 2 \mathrm{~V} \]…
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