TS EAMCET · Physics · Alternating Current
In a series LCR circuit, if the current leads the source voltage, then
- A \(X_{\mathrm{C}} \gt X_{\mathrm{L}}\)
- B \(X_{\mathrm{L}} \gt X_{\mathrm{C}}\)
- C \(X_L=X_C \neq 0\)
- D \(X_L=X_C=0\)
Answer & Solution
Correct Answer
(A) \(X_{\mathrm{C}} \gt X_{\mathrm{L}}\)
Step-by-step Solution
Detailed explanation
The phase difference between the current and the voltage in the series LCR circuit is \(\tan \phi=\frac{\mathrm{X}_{\mathrm{L}}-\mathrm{X}_{\mathrm{C}}}{\mathrm{R}}\) And from phasor diagram, if the current is leading the voltage, then the phase difference should be negative. so…
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