TS EAMCET · Physics · Mechanical Properties of Solids
A copper wire and an aluminium wire have lengths in the ratio \(5: 2\), diameters in the ratio \(4: 3\) and forces applied in the ratio \(4: 5\). Find the ratio of increase in length of the copper wire to that aluminium wire. (Let \(Y_{\mathrm{Cu}}=1.1 \times 10^{11} \mathrm{Nm}^{-2}, Y_{\mathrm{Al}}=0.7 \times 10^{11} \mathrm{Nm}^{-2}\) )
- A \(\frac{176}{63}\)
- B \(\frac{63}{88}\)
- C \(\frac{189}{11}\)
- D \(\frac{33}{89}\)
Answer & Solution
Correct Answer
(B) \(\frac{63}{88}\)
Step-by-step Solution
Detailed explanation
Given, ratio of length of copper wire and aluminium wire, \(l_1: l_2=5: 2\) and diameter ratio of the wire \(=d_1: d_2=4: 3\) \(\therefore \quad r_1: r_2=2: \frac{3}{2}\) If \(\Delta l_1\) and \(\Delta l_2\) are increase in the length of copper and aluminium wire, respectively…
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