TS EAMCET · Physics · Kinetic Theory of Gases
The volume of one mole of the gas is changed from \(V\) to \(2 V\) at constant pressure \(p\). If \(\gamma\) is the ratio of specific heats of the gas, change in internal energy of the gas is
- A \(\frac{r . p V}{\gamma-1}\)
- B \(\frac{r}{\gamma-1}\)
- C \(p V\)
- D \(\frac{p V}{\gamma-1}\)
Answer & Solution
Correct Answer
(D) \(\frac{p V}{\gamma-1}\)
Step-by-step Solution
Detailed explanation
\( \Delta U = n C_v \Delta T = n \left( \frac{R}{\gamma - 1} \right) \Delta T \) \( p \Delta V = n R \Delta T \implies p(2V - V) = pV = n R \Delta T \) \( \Delta U = \frac{1}{\gamma - 1} (pV) = \frac{pV}{\gamma - 1} \)
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