TS EAMCET · Physics · Motion In One Dimension
A car travelling at \(15 \mathrm{~m} / \mathrm{s}\) overtake another car travelling at \(10 \mathrm{~m} / \mathrm{s}\). Assuming, each car is \(4 \mathrm{~m}\) long. What is the time taken during the overtake?
- A \(1.6 \mathrm{~s}\)
- B \(0.8 \mathrm{~s}\)
- C \(0.6 \mathrm{~s}\)
- D \(0.4 \mathrm{~s}\)
Answer & Solution
Correct Answer
(A) \(1.6 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
The motion of two car \(A\) and \(B\) is shown in the figure. Relative velocity of car \(A\) w.r.t. car \(B\) is \(v_{A B}=v_A-v_B=15-10=5 \mathrm{~m} / \mathrm{s}\) Distance to be covered for overtake is given as \(s=4 m+4 m=8 m\) Time taken by cars to cross \(=\) Distance…
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