TS EAMCET · Physics · Work Power Energy
A ball of mass \(1 \mathrm{~kg}\) moves in a straight line with velocity \(v=c x^a\), where \(c=1\) (SI unit) and \(\alpha\) is a constant. If the work done by the net force during its displacement from \(\mathrm{x}=0\) to \(\mathrm{x}=4 \mathrm{~m}\) is \(128 \mathrm{~J}\), then the \(\alpha\) is
- A 1
- B \(\frac{3}{2}\)
- C 2
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
From work - Energy theorem Work done \(=\) Change in kinetic energy \[ \begin{aligned} 128 & =\frac{1}{2} m v_2^2-\frac{1}{2} m v_1^2 \\ 128 & =\frac{1}{2} v_2^2-\frac{1}{2} v_1^2 \end{aligned} \] ...(i) \((\because \mathrm{vm}=118)\) We have \(\mathrm{v}=\mathrm{cx}^\alpha\)…
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