TS EAMCET · Physics · Motion In Two Dimensions
A projectile is given an initial velocity of where, is along the ground and is along the vertical. Assuming , if the equation of its trajectory can be written as , then the value of is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(B)
Step-by-step Solution
Detailed explanation
The initial velocity u=32+42=5 m s-1 and the angle of projection θ=tan-143=53°. The equation of trajectory of a projectile is y=xtanθ-gx22u2cos2θ⇒y=43x-10×252×25×9x2=43x-59x2⇒y=1912x-5x2 Therefore, β=12 and γ=-5.
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