TS EAMCET · Physics · Gravitation
A ring has a mass \(M\) and radius \(R\). The distance of the point on its geometric axis from its centre at which the gravitational field is strongest is
- A \(\frac {R}{2}\)
- B \(\frac {R}{4}\)
- C \(\frac {R}{\sqrt 3}\)
- D \(\frac {R}{\sqrt 2}\)
Answer & Solution
Correct Answer
(D) \(\frac {R}{\sqrt 2}\)
Step-by-step Solution
Detailed explanation
Gravitational field from the centre is given by \(\mathrm{E}=\frac{\mathrm{GMx}}{\left(\mathrm{R}^2+\mathrm{x}^2\right)^{3 / 2}}\) The gravitational field is strongest. So…
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