TS EAMCET · Physics · Units and Dimensions
The dimensional formula of \(\frac{1}{2} \mu_0 H^2\) ( \(\mu=\) permeability of free space and \(H=\) magnetic field intensity) is
- A \(\left[\mathrm{MLT}^{-1}\right]\)
- B \(\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]\)
- C \(\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]\)
- D \(\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]\)
Answer & Solution
Correct Answer
(C) \(\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & {\left[\mu_0\right]=\left[\mathrm{MLT}^{-2} \mathrm{~A}^{-2}\right] \text { and }[H]=\left[\mathrm{AL}^{-1}\right]} \\ & \therefore \\ & {\left[\frac{1}{2} \mu_0 H^2\right]=\left[\mathrm{MLT}^{-2}…
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