TS EAMCET · Physics · Laws of Motion
A force separately produces accelerations of \(18 \mathrm{~ms}^{-2}, 9 \mathrm{~ms}^{-2}\) and \(6 \mathrm{~ms}^{-2}\) in three bodies of masses \(\mathrm{P}, \mathrm{Q}\) and R respectively. If the same force is applied on a body of mass \(\mathrm{P}+\mathrm{Q}+\mathrm{R}\), then the acceleration of that body is
- A \(3 \mathrm{~ms}^{-2}\)
- B \(6 \mathrm{~ms}^{-2}\)
- C \(2 \mathrm{~ms}^{-2}\)
- D \(33 \mathrm{~ms}^{-2}\)
Answer & Solution
Correct Answer
(A) \(3 \mathrm{~ms}^{-2}\)
Step-by-step Solution
Detailed explanation
\(P = \frac{F}{18}, Q = \frac{F}{9}, R = \frac{F}{6}\) \(M_{total} = P+Q+R = \frac{F}{18} + \frac{F}{9} + \frac{F}{6} = F \left( \frac{1+2+3}{18} \right) = F \left( \frac{6}{18} \right) = \frac{F}{3}\) \(a = \frac{F}{M_{total}} = \frac{F}{F/3} = 3 \mathrm{~ms}^{-2}\)
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