TS EAMCET · Physics · Current Electricity
A cylindrical resistor of radius \(7.0 \mathrm{~mm}\) and length 4.0 \(\mathrm{cm}\) is made of material that has a resistivity of \(10^{-6} \Omega . \mathrm{m}\). If the energy is dissipated at rate \(1.54 \mathrm{~W}\) in the resistor, then the current density is
- A \(\frac{10^6}{\sqrt{\pi}} \mathrm{A} / \mathrm{m}^2\)
- B \(5 \times 10^5 \mathrm{~A} / \mathrm{m}^2\)
- C \(\sqrt{\pi} \times 10^5 \mathrm{~A} / \mathrm{m}^2\)
- D \(8.5 \times 10^4 \mathrm{~A} / \mathrm{m}^2\)
Answer & Solution
Correct Answer
(B) \(5 \times 10^5 \mathrm{~A} / \mathrm{m}^2\)
Step-by-step Solution
Detailed explanation
\(P=i^2 R \Rightarrow i=\sqrt{\frac{P}{R}}=\sqrt{\frac{P A}{\rho l}}\)…
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