TS EAMCET · Physics · Waves and Sound
When a vibrating tuning fork is placed on a sound box of a sonometer, 8 beats per second are heard when the length of the sonometer wire is kept at \(101 \mathrm{~cm}\) or \(100 \mathrm{~cm}\). Then the frequency of the tuning fork is (Consider that the tension in the wire is kept constant)
- A \(1616 \mathrm{~Hz}\)
- B \(1608 \mathrm{~Hz}\)
- C \(1632 \mathrm{~Hz}\)
- D \(1600 \mathrm{~Hz}\)
Answer & Solution
Correct Answer
(B) \(1608 \mathrm{~Hz}\)
Step-by-step Solution
Detailed explanation
We have, \(n l=\) constant \(\begin{aligned} n_1 l_1 & =n_2 l_2 \\ (n+8) 100 & =(n-8) 101 \\ \frac{n+8}{n-8} & =\frac{101}{100} \\ \frac{n}{8} & =\frac{201}{1} \\ n & =1608\end{aligned}\)
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