TS EAMCET · Maths · Probability
If the probability distribution of a random variable \(X\) is as follows, then the variance of \(X\) is \begin{array}{|l|c|c|c|c|}\hlineX=x & 2 & 3 & 5 & 9 \\hlineP(X=x) & k & 2 k & 3 k^2 & k^2 \\hline\end{array}
- A \(\frac{61}{4}\)
- B \(\frac{7}{2}\)
- C 12
- D 3
Answer & Solution
Correct Answer
(D) 3
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Detailed explanation
\(\begin{array}{|c|c|c|c|c|}\hline \boldsymbol{X}=\boldsymbol{x} & 2 & 3 & 5 & 9 \\\hline \boldsymbol{P}(\boldsymbol{X}=\boldsymbol{x}) & K & 2 K & 3 K^2 & K^2 \\\hline\end{array}\) We know \(\Sigma P=1,4 K^2+2 K+K=1\) \(K=\frac{1}{4}\) or \((-1\) rejected) (\(P\) is always…
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