TS EAMCET · Maths · Definite Integration
\(\int_0^{16} \frac{\sqrt{x}}{1+\sqrt{x}} d x=\)
- A \(8+2 \log 2\)
- B \(8+\log 2\)
- C \(8+2 \log 5\)
- D \(4+\log 5\)
Answer & Solution
Correct Answer
(C) \(8+2 \log 5\)
Step-by-step Solution
Detailed explanation
\(I=\int_0^{16} \frac{\sqrt{x}}{1+\sqrt{x}} d x=\int_0^{16}\left(1-\frac{1}{1+\sqrt{x}}\right) d x\)…
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