TS EAMCET · Maths · Complex Number
If \(\alpha\) is a root of the equation \(x^2-x+1=0\), then \(\left(\alpha+\frac{1}{\alpha}\right)^3+\left(\alpha^2+\frac{1}{\alpha^2}\right)^3+\left(\alpha^3+\frac{1}{\alpha^3}\right)^3+\left(\alpha^4+\frac{1}{\alpha^4}\right)^3=\)
- A \(0\)
- B \(1\)
- C \(-3\)
- D \(-9\)
Answer & Solution
Correct Answer
(D) \(-9\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { } x^2-x+1=0 \\ & \alpha^2-\alpha+1=0 \Rightarrow \alpha+\frac{1}{\alpha}=1 \\ & \Rightarrow \alpha^2+\frac{1}{\alpha^2}+2=1 \Rightarrow \alpha^2+\frac{1}{\alpha^2}=-1\end{aligned}\)…
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