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TS EAMCET · Maths · Properties of Triangles

In ABC, if a=5 and tanA-B2=14tanA+B2, then a2-b2=

  1. A 2
  2. B 3
  3. C 4
  4. D 5
Verified Solution

Answer & Solution

Correct Answer

(C) 4

Step-by-step Solution

Detailed explanation

Given that, tanA-B2=14tanA+B2 ⇒sinA-B2cosA-B2=14sinA+B2cosA+B2 ⇒4sinA-B2cosA+B2=sinA+B2cosA-B2 ⇒2sinA-sinB=12sinA-sin-B ⇒4sinA-4sinB=sinA+sinB ⇒3sinA=5sinB ⇒5sinA=3sinB [From sine rule] ⇒asinA=bsinB ∴b=3 Now, a2-b2=52-32 =25-9 =16…