TS EAMCET · Maths · Circle
Let \(A=(2,0)\) and \(B=(0,-2)\). Let \(P\) be any point such that the sum of the distances of \(P\) from \(A\) and \(B\) is 4 . Then the equation of the locus of the point \(P\) is
- A \(3 x^2-2 x y+3 y^2-4 x+12 y+16=0\)
- B \(3 x^2-2 x y+3 y^2-8 x+8 y=0\)
- C \(3 x^2+2 x y+3 y^2+8 x-8 y=0\)
- D \(3 x^2+2 x y+3 y^2+4 x-12 y+16=0\)
Answer & Solution
Correct Answer
(B) \(3 x^2-2 x y+3 y^2-8 x+8 y=0\)
Step-by-step Solution
Detailed explanation
Let \(P(x, y)\) be the point. Hence \(P A+P B=4\)…
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