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TS EAMCET · Maths · Determinants

Let \(\left|\begin{array}{ccc}x^2+x+1 & x+1 & 2 x-3 \\ 3 x^2-1 & x+2 & x-1 \\ x^2+5 x+1 & 2 x+3 & x+4\end{array}\right|\) \(=a x^4+b x^3+c x^2+d x+e\) be an identity in \(x\). If \(a, b, c, d\) are known, then the value of \(e\) is

  1. A 29
  2. B 24
  3. C 16
  4. D 9
Verified Solution

Answer & Solution

Correct Answer

(A) 29

Step-by-step Solution

Detailed explanation

We have, \[ \begin{array}{r} \left|\begin{array}{ccc} x^2+x+1 & x+1 & 2 x-3 \\ 3 x^2-1 & x+2 & x-1 \\ x^2+5 x+1 & 2 x+3 & x+4 \end{array}\right| \\ =a x^4+b x^3+c x^2+d x+e \end{array} \] Put \(x=0\) on both sides, we get…