TS EAMCET · Maths · Determinants
Let \(\left|\begin{array}{ccc}x^2+x+1 & x+1 & 2 x-3 \\ 3 x^2-1 & x+2 & x-1 \\ x^2+5 x+1 & 2 x+3 & x+4\end{array}\right|\) \(=a x^4+b x^3+c x^2+d x+e\) be an identity in \(x\). If \(a, b, c, d\) are known, then the value of \(e\) is
- A 29
- B 24
- C 16
- D 9
Answer & Solution
Correct Answer
(A) 29
Step-by-step Solution
Detailed explanation
We have, \[ \begin{array}{r} \left|\begin{array}{ccc} x^2+x+1 & x+1 & 2 x-3 \\ 3 x^2-1 & x+2 & x-1 \\ x^2+5 x+1 & 2 x+3 & x+4 \end{array}\right| \\ =a x^4+b x^3+c x^2+d x+e \end{array} \] Put \(x=0\) on both sides, we get…
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