TS EAMCET · Maths · Binomial Theorem
If \(\frac{3 \mathrm{x}+2}{(\mathrm{x}+1)\left(2 \mathrm{x}^2+3\right)}=\frac{\mathrm{A}}{\mathrm{x}+1}+\frac{\mathrm{Bx}+\mathrm{C}}{2 \mathrm{x}^2+3}\), then \(\mathrm{A}-\mathrm{B}+\mathrm{C}=\)
- A \(2\)
- B \(1\)
- C \(3\)
- D \(6\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(\frac{3 x+2}{(x+1)\left(2 x^2+3\right)}=\frac{\mathrm{A}}{x+1}+\frac{\mathrm{B} x+\mathrm{C}}{2 x^2+3}\)…
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