TS EAMCET · Maths · Parabola
The points of intersection of the parabolas \(y^2=5 x\) and \(x^2=5 y\) lie on the line
- A \(x+y=10\)
- B \(x-2 y=0\)
- C \(x-y=0\)
- D \(2 x-y=0\)
Answer & Solution
Correct Answer
(C) \(x-y=0\)
Step-by-step Solution
Detailed explanation
Given equation of parabolas \[ y^2=5 x \] and \(\quad x^2=5 y\) Now, \(\quad x^2=5 y\) \(\Rightarrow \quad y=\frac{x^2}{5}\) On substituting \(y=\frac{x^2}{5}\) in Eq. (i), we get \[ \left(\frac{x^2}{5}\right)^2=5 x \] \[ \Rightarrow \quad \frac{x^4}{25}=5 x \]…
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