TS EAMCET · Maths · Quadratic Equation
If \(\alpha, \beta, \gamma\) are the roots of \(x^3+p x^2+q x+r=0\), then \(\alpha^3+\beta^3+\gamma^3=\)
- A \(p^3-3 p q+r\)
- B \(p^2-2 p q+r\)
- C \(3 p q-3 r-p^3\)
- D \(3 p q+3 r+p^3\)
Answer & Solution
Correct Answer
(C) \(3 p q-3 r-p^3\)
Step-by-step Solution
Detailed explanation
\(\alpha, \beta, \gamma\) are roots of \(x^3+p x^2+q x+\gamma=0\), then \(\alpha^3+\beta^3+\gamma^3=\) ? \[ \alpha+\beta+\gamma=-p \]…
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