TS EAMCET · Maths · Parabola
If the normals drawn at the points \(\mathrm{P}\left(\frac{3}{4}, \frac{3}{2}\right)\) and \(\mathrm{Q}(3,3)\) on the parabola \(y^2=3 x\) intersect again on \(y^2=3 x\) at R, then \(\mathrm{R}=\)
- A \((12,6)\)
- B \(\left(\frac{27}{4},-\frac{9}{2}\right)\)
- C \(\left(\frac{3}{16}, \frac{3}{4}\right)\)
- D \(\left(\frac{1}{12},-\frac{1}{2}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{27}{4},-\frac{9}{2}\right)\)
Step-by-step Solution
Detailed explanation
\(a = \frac{3}{4}\) \(P\left(\frac{3}{4}, \frac{3}{2}\right) = (at_1^2, 2at_1) \implies t_1 = 1\) \(Q(3,3) = (at_2^2, 2at_2) \implies t_2 = 2\) \(R = (at_3^2, 2at_3)\) where \(t_3 = -(t_1+t_2)\) \(t_3 = -(1+2) = -3\)…
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