TS EAMCET · Maths · Permutation Combination
The number of ways of arranging 8 men and 4 women around a circular table such that no two women can sit together is
- A \(8 !\)
- B \(4 !\)
- C \(8 ! 4 !\)
- D \(7 !{ }^8 P_4\)
Answer & Solution
Correct Answer
(D) \(7 !{ }^8 P_4\)
Step-by-step Solution
Detailed explanation
The number of ways of arranging 8 men \(=7\) ! The number of ways of arranging 4 women such that no two women can sit together \(={ }^8 P_4\) \(\therefore\) Required number of ways \(=7 !^8 P_4\).
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