TS EAMCET · Chemistry · Thermodynamics (C)
The standard enthalpy of formation \(\left(\Delta_f H^{\circ}\right)\) of ammonia is \(-46.2 \mathrm{~kJ} \mathrm{~mol}^{-1}\). What is the \(\Delta_r H^{-}\)of the following reaction? \(\mathrm{N}_2(\mathrm{~g})+3 \mathrm{H}_2(\mathrm{~g}) \rightarrow 2 \mathrm{NH}_3(\mathrm{~g})\)
- A -46.2 kJ
- B +46.2 kJ
- C -92.4 kJ
- D -184.8 kJ
Answer & Solution
Correct Answer
(C) -92.4 kJ
Step-by-step Solution
Detailed explanation
\(\Delta_{\mathrm{r}} \mathrm{H}^{\circ}=\Sigma \Delta_{\mathrm{f}} \mathrm{H}^{\circ}\) (products) \(-\Sigma \Delta_{\mathrm{f}} \mathrm{H}^{\circ}\) (Reactants)…
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