TS EAMCET · Maths · Quadratic Equation
If \(\alpha, \beta\) are the roots of quadratic equation \(x^2+b x+c=0\) such that \(\alpha^2+\beta^2=5\) and \(\alpha^3+\beta^3=9\), then \(b+c=\)
- A –5
- B –1
- C 1
- D 5
Answer & Solution
Correct Answer
(B) –1
Step-by-step Solution
Detailed explanation
Given quadratic equation is \({x}^2+{bx}+{c}=0\) Here, \(\alpha \times \beta\) are roots of equation. Take square both sides, \( \alpha^2+\beta^2+2 \alpha \beta=b^2 \) Here, \(\alpha^2+\beta^2=5\)…
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