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TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure

Match the following List-I (Molecule) List - II (Shape) A. \(\mathrm{XeF}_4\) I. Square pyramid, B. \(\mathrm{ClF}_3\) II. Pentagonal bipyramidal C. \(\mathrm{BrF}_5\) III. Square planar D. \(\mathrm{IF}_7\) IV. Bent T-Shape

  1. A A-III; B-II; C-I; D-IV
  2. B A-III; B-II; C-IV; D-I
  3. C A-III; B-IV; C-I; D-II
  4. D A-IV; B-II; C-I; D-III
Verified Solution

Answer & Solution

Correct Answer

(C) A-III; B-IV; C-I; D-II

Step-by-step Solution

Detailed explanation

\(\mathrm{XeF}_4\) is square planar in shape due to four bond pairs and two lone pairs that form an octahedral geometry. \(\mathrm{ClF}_3\) is Bent T-shaped due to three bond pairs and two lone pairs around the central \(\mathrm{Cl}\) atom that together form a trigonal…
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