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TS EAMCET · Maths · Pair of Lines

Let the line \(\mathrm{L}_1\) passing through the point of intersection of the lines \(2 x+3 y-5=0\) and \(4 x-5 y+7=0\) divide the line segment joining the points \((2,3)\) and \((1,-1)\) in the ratio \(2: 1\). If the equation of \(L_1\) is \(a x+b y=1\), then \(33(a-b)=\)

  1. A \(-1\)
  2. B \(0\)
  3. C \(1\)
  4. D \(2\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1\)

Step-by-step Solution

Detailed explanation

Equation of line passing through point of intersection of \(L=0\) and \(l=0\) is \(L+\lambda l=0\) \[ \begin{aligned} & \Rightarrow(2 x+3 y-5)+\lambda(4 x-5 y+7)=0 \\ & L_1:(2+4 \lambda) x+(3-5 \lambda) y+(7 \lambda-5)=0 \end{aligned} \] \(\because L_1\) divides the line joining…