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TS EAMCET · Maths · Probability

If two biased dice are rolled simultaneously until a sum of the number appeared on these dice is either 7 or 11 , then the probability that 7 comes before 11 , is

  1. A \(\frac{3}{8}\)
  2. B \(\frac{3}{4}\)
  3. C \(\frac{5}{6}\)
  4. D \(\frac{2}{9}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{3}{4}\)

Step-by-step Solution

Detailed explanation

Let \(A\) be the events sum appeared on two unbiased dice is 7 and \(B\) be the event sum appeared on two unbiased dice is either 7 or 11 . \[ \therefore P(A)=\frac{6}{36}, P(B)=\frac{6}{36}+\frac{2}{36}=\frac{2}{9} \] \(\therefore\) Required probability…