KCET · Maths · Permutation Combination
The number of ways in which \( 5 \) girls and \( 3 \) boys can be seated in a row so that no two boys
are togetheris
- A \( 14040 \)
- B \( 14440 \)
- C \( 14000 \)
- D \( 14400 \)
Answer & Solution
Correct Answer
(D) \( 14400 \)
Step-by-step Solution
Detailed explanation
Number of boys are 3 and number of girls are 5 .
So, required ways is given by
\(5 ! \times{ }^{6} C_{3} \times 3 !\)
\(=120 \times 6 \times 5 \times 4=120 \times 120=14400\)
So, required ways is given by
\(5 ! \times{ }^{6} C_{3} \times 3 !\)
\(=120 \times 6 \times 5 \times 4=120 \times 120=14400\)
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