ExamBro
ExamBro
KCET · Maths · Binomial Theorem

The digit in the unit place of the number \(2009 !+3^{7886}\) is

  1. A 7
  2. B 3
  3. C 1
  4. D 9
Verified Solution

Answer & Solution

Correct Answer

(D) 9

Step-by-step Solution

Detailed explanation

The digit in the unit place of (2009)! is 0 . Now, \(3^{1}=3, \quad 3^{2}=9, \quad 3^{3}=27, \quad 3^{4}=81\), \(3^{5}=243\)
\[
\therefore \quad 3^{7886}=\left(3^{4}\right)^{1971} 3^{2}
\]
The digit in the unit place of \(3^{7886}\) is 9 .
\(\therefore\) The digit in the unit place of (2009)! \(+3^{7886}\) is \(9 .\)