KCET · Physics · Wave Optics
A parallel beam of light of wavelength \(6000 Å\) gets diffracted by a single slit of width \(0.3 \mathrm{~mm}\). The angular position of the first minima of diffracted light is
- A \(2 \times 10^{-3} \mathrm{rad}\)
- B \(3 \times 10^{-3} \mathrm{rad}\)
- C \(1.8 \times 10^{-3} \mathrm{rad}\)
- D \(6 \times 10^{-3} \mathrm{rad}\)
Answer & Solution
Correct Answer
(A) \(2 \times 10^{-3} \mathrm{rad}\)
Step-by-step Solution
Detailed explanation
Given, \(\lambda=6000 Å=6000 \times 10^{-10} \mathrm{~m}\) and \(n=0.3 \mathrm{~mm}=0.3 \times 10^{-3} \mathrm{~m}\) \(0.3 \times 10^{-3} \times \sin \theta=6000 \times 10^{-10}\)
\[
\sin \theta=2 \times 10^{-3}
\]
or \(\theta=2 \times 10^{-3} \mathrm{rad}\)
\[
\sin \theta=2 \times 10^{-3}
\]
or \(\theta=2 \times 10^{-3} \mathrm{rad}\)
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