KCET · Chemistry · Thermodynamics (C)
A: Entropy of a perfect crystalline solid at absolute zero approaches zero.
B: For spontaneity of a reaction, \(T\Delta S > \Delta H\).
Among the two statements given above, identify the correct answer from the options given below.
- A Both '\(A\)' and '\(B\)' are true
- B 'A' is true but 'B' is false
- C Both 'A' and 'B' are false
- D '\(A\)' is false but '\(B\)' is true
Answer & Solution
Correct Answer
(A) Both '\(A\)' and '\(B\)' are true
Step-by-step Solution
Detailed explanation
Statement A is based on the third law of thermodynamics, which states that the entropy of a perfectly crystalline solid approaches zero as the temperature approaches absolute zero. Thus, Statement A is true.
For a reaction to be spontaneous at constant temperature and pressure, the change in Gibbs free energy (\(\Delta G\)) must be negative (\(\Delta G < 0\)).
From the Gibbs-Helmholtz equation:
\(\Delta G = \Delta H - T\Delta S\)
For spontaneity, \(\Delta G < 0\)
\(\Rightarrow \Delta H - T\Delta S < 0\)
\(\Rightarrow T\Delta S > \Delta H\)
Thus, Statement B is also true.
Both Statement A and Statement B are true.
Answer: Both '\(A\)' and '\(B\)' are true
For a reaction to be spontaneous at constant temperature and pressure, the change in Gibbs free energy (\(\Delta G\)) must be negative (\(\Delta G < 0\)).
From the Gibbs-Helmholtz equation:
\(\Delta G = \Delta H - T\Delta S\)
For spontaneity, \(\Delta G < 0\)
\(\Rightarrow \Delta H - T\Delta S < 0\)
\(\Rightarrow T\Delta S > \Delta H\)
Thus, Statement B is also true.
Both Statement A and Statement B are true.
Answer: Both '\(A\)' and '\(B\)' are true
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