KCET · Maths · Sets and Relations
Let \(A=\{2,3,4,5, \ldots, 16,17,18\}\). Let \(R\) be the relation on the set \(A\) of ordered pairs of positive integers defined by \((a, b) R(c, d)\) if and only if \(a d=b c\) for all \((a, b),(c, d)\) in \(A \times A\). Then, the number of ordered pairs of the equivalence class of \((3,2)\) is
- A \(4\)
- B \(5\)
- C \(6\)
- D \(7\)
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
Let \((3,2) R(x, y)\)
\(\Rightarrow \quad 3 y=2 x\)
This is possible in the cases
\(\begin{aligned} & x=3, y=2 \\ & x=6, y=4 \\ & x=9, y=6 \\ & x=12, y=8 \\ & x=15, y=10\end{aligned}\)
\(x=18, y=12\)
Hence, total pairs are 6 .
\(\Rightarrow \quad 3 y=2 x\)
This is possible in the cases
\(\begin{aligned} & x=3, y=2 \\ & x=6, y=4 \\ & x=9, y=6 \\ & x=12, y=8 \\ & x=15, y=10\end{aligned}\)
\(x=18, y=12\)
Hence, total pairs are 6 .
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