KCET · Chemistry · Redox Reactions
In which of the following compounds, an element exhibits two different oxidation states?
- A \(\mathrm{NH}_4 \mathrm{NO}_3\)
- B \(\mathrm{N}_2 \mathrm{H}_4\)
- C \(\mathrm{N}_3 \mathrm{H}\)
- D \(\mathrm{NH}_2 \mathrm{CONH}_2\)
Answer & Solution
Correct Answer
(A) \(\mathrm{NH}_4 \mathrm{NO}_3\)
Step-by-step Solution
Detailed explanation
In \(\mathrm{NH}_4 \mathrm{NO}_3, \mathrm{~N}\) exhibits two different oxidation states. Actually \(\mathrm{NH}_4 \mathrm{NO}_3\) exists as \(\mathrm{NH}_4^{+}\) and \(\mathrm{NO}_3^{-}\). Oxidation state of \(\mathrm{N} \mathrm{in}_4^{+}\)is -3 and in \(\mathrm{NO}_3^{-}\)is +5 .
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