KCET · Chemistry · Coordination Compounds
Which of the following system in an octahedral complex has maximum unpaired electrons?
- A \(d^9\) (high spin)
- B \(d^6\) (low spin)
- C \(d^4\) (low spin)
- D \(d^7\) (high spin)
Answer & Solution
Correct Answer
(D) \(d^7\) (high spin)
Step-by-step Solution
Detailed explanation
\(\begin{array}{|c|c|}
\hline & \begin{array}{c}
\text { Unpaired } \\
\text { electrons }
\end{array} \\
\hline \begin{array}{c}
d^4 \text { (low spin) } \\
-16
\end{array} & 2 \\
\hline \begin{array}{c}
d^7 \text { (high } \\
\text { spin) }-1
\end{array} & 3 \\
\hline \begin{array}{c}
d^9 \text { (high } \\
\text { spin) }-1
\end{array} & 1 \\
\hline
\end{array}\)
\(\therefore d^7\) (high spin) system has maximum unpaired electrons.
\hline & \begin{array}{c}
\text { Unpaired } \\
\text { electrons }
\end{array} \\
\hline \begin{array}{c}
d^4 \text { (low spin) } \\
-16
\end{array} & 2 \\
\hline \begin{array}{c}
d^7 \text { (high } \\
\text { spin) }-1
\end{array} & 3 \\
\hline \begin{array}{c}
d^9 \text { (high } \\
\text { spin) }-1
\end{array} & 1 \\
\hline
\end{array}\)
\(\therefore d^7\) (high spin) system has maximum unpaired electrons.
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