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KCET · Physics · Laws of Motion

A horizontal force of \(5\) N is applied on a stationary body of mass \(5\) kg, which is initially at rest on a frictionless table. The change in kinetic energy of the body in \(10\) s is

  1. A \(25\) J
  2. B Zero
  3. C \(125\) J
  4. D \(250\) J
Verified Solution

Answer & Solution

Correct Answer

(D) \(250\) J

Step-by-step Solution

Detailed explanation

Given, mass of the body \(m = 5\) kg

Horizontal force \(F = 5\) N

Acceleration of the body \(a = \dfrac{F}{m} = \dfrac{5}{5} = 1\) m/s\(^2\)

Initial velocity \(u = 0\)

Time \(t = 10\) s

Using the equation of motion \(v = u + at\),

\(v = 0 + 1 \times 10 = 10\) m/s

Initial kinetic energy \(K_i = 0\)

Final kinetic energy \(K_f = \dfrac{1}{2}mv^2 = \dfrac{1}{2} \times 5 \times (10)^2 = 250\) J

Change in kinetic energy \(\Delta K = K_f - K_i = 250 - 0 = 250\) J

Answer: \(250\) J